How to extract filename from the path?

[eduspk]

Hi All

I want to extract file name from the path

Ex:

..../../default/folder/temp.txt

output:

Filename
temp.txt

[vnravikumar · Accepted solution]

Hi @eduspk

Try like and let me know

| makeresults 
| eval path="..../../default/folder/temp.txt" 
| rex field=path ".*\/(?<filename>.*)$"

[eduspk]

Thanks for quick reply.