Splunk Search

substr can't get the correct value?

flora123
Path Finder

Hi,all

I want to use "substr" to get what I want.

A=1420014

... |eval A=if(substr(A, 1,2)="14",replace(A, "14", "0"),A) |table A

A will become "02000".

But it should be "020014".

Could anyone tell me what's worng? Can't I use substr by this way?

Thanks a lot. 😃

Tags (1)
1 Solution

dwaddle
SplunkTrust
SplunkTrust

The replace operator will replace every occurence of a value in a string. From http://www.splunk.com/base/Documentation/latest/SearchReference/CommonEvalFunctions :

This function returns a string formed by substituting string Z for every occurrence of regex string Y in string X. The third argument Z can also reference groups that are matched in the regex.

Given your example above, there are a couple of ways to attack it. If you're always wanting to replace the "14" (or whatever) at the beginning, you should be able to take advantage of the fact that replace uses regexes, and do something like:

... | eval A=if(substr(A,1,2)="14",replace(A,"^14","0"),A) | table A

Or you can accomplish the same thing with string concatenation, similar to:

... | eval A=if(substr(A,1,2)="14", "0".substr(A,3), A) | table A

View solution in original post

0 Karma

dwaddle
SplunkTrust
SplunkTrust

The replace operator will replace every occurence of a value in a string. From http://www.splunk.com/base/Documentation/latest/SearchReference/CommonEvalFunctions :

This function returns a string formed by substituting string Z for every occurrence of regex string Y in string X. The third argument Z can also reference groups that are matched in the regex.

Given your example above, there are a couple of ways to attack it. If you're always wanting to replace the "14" (or whatever) at the beginning, you should be able to take advantage of the fact that replace uses regexes, and do something like:

... | eval A=if(substr(A,1,2)="14",replace(A,"^14","0"),A) | table A

Or you can accomplish the same thing with string concatenation, similar to:

... | eval A=if(substr(A,1,2)="14", "0".substr(A,3), A) | table A
0 Karma

flora123
Path Finder

Wonderful!Thanks a lot.

0 Karma
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