Splunk Search

Replace A pattern Splunk

baranova
New Member

Hello Guys ,

I have a field Month that have values like this

1-2013
10-2014
9-2014

i would like to get 0X-YYYY if month <10

so 1-2013 becomes 01-2013
10-2014 stays 10-2014
9-2014 becomes 09-2014

I've tried rex mode=sed field="Month" "s/(^[0-9]-.*)/0\1/" (it works fine on linux but not on Splunk ..)

Could you help me ?

Thanks !

Tags (1)
0 Karma

grijhwani
Motivator

I'm not familiar with sed mode, but have you tried escaping the square brackets with a backslash. Whenever a regex fails to match the expected results my first thought is always escaping special characters. Some regex modes assume special meaning unless expressly suppressed whilst others are the reverse, and just for fun some assume special meaning for one subset whilst not for others. It can be mind-bendingly confusing.

0 Karma

HiroshiSatoh
Champion

about using eval?

・・・|eval Month=if(len(Month)==6,"0"+Month,Month)

0 Karma
Got questions? Get answers!

Join the Splunk Community Slack to learn, troubleshoot, and make connections with fellow Splunk practitioners in real time!

Meet up IRL or virtually!

Join Splunk User Groups to connect and learn in-person by region or remotely by topic or industry.

Get Updates on the Splunk Community!

[Puzzles] Solve, Learn, Repeat: Matching cron expressions

This puzzle (first published here) is based on matching timestamps to cron expressions.All the timestamps ...

Why Splunk Customers Should Attend Cisco Live 2026 Las Vegas

Why Splunk Customers Should Attend Cisco Live 2026 Las Vegas     Cisco Live 2026 is almost here, and this ...

Data Management Digest – May 2026

Welcome to the May 2026 edition of Data Management Digest!   As your trusted partner in data innovation, the ...