Splunk Search

Replace A pattern Splunk

baranova
New Member

Hello Guys ,

I have a field Month that have values like this

1-2013
10-2014
9-2014

i would like to get 0X-YYYY if month <10

so 1-2013 becomes 01-2013
10-2014 stays 10-2014
9-2014 becomes 09-2014

I've tried rex mode=sed field="Month" "s/(^[0-9]-.*)/0\1/" (it works fine on linux but not on Splunk ..)

Could you help me ?

Thanks !

Tags (1)
0 Karma

grijhwani
Motivator

I'm not familiar with sed mode, but have you tried escaping the square brackets with a backslash. Whenever a regex fails to match the expected results my first thought is always escaping special characters. Some regex modes assume special meaning unless expressly suppressed whilst others are the reverse, and just for fun some assume special meaning for one subset whilst not for others. It can be mind-bendingly confusing.

0 Karma

HiroshiSatoh
Champion

about using eval?

・・・|eval Month=if(len(Month)==6,"0"+Month,Month)

0 Karma
Got questions? Get answers!

Join the Splunk Community Slack to learn, troubleshoot, and make connections with fellow Splunk practitioners in real time!

Meet up IRL or virtually!

Join Splunk User Groups to connect and learn in-person by region or remotely by topic or industry.

Get Updates on the Splunk Community!

Announcing Modern Navigation: A New Era of Splunk User Experience

We are excited to introduce the Modern Navigation feature in the Splunk Platform, available to both cloud and ...

Best Practices: Splunk auto adjust pipeline queue

When you enable autoAdjustQueue in Splunk, maxSize should be understood as the queue size Splunk starts with ...

Request for Professional Development: Attending .conf26

Winning Over the Boss: Your Pass to .conf26 conf26 is going to be here before you know it. If don't already ...