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- How to extract filename from fields?
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dhirendra761
Contributor
06-19-2019
12:22 AM
I am trying to extract a filename Nsences_2016_10_10_12_50.csv from below field value.
D:\Program Files\X620\ABC\TGF\Files\sss\Nsences_2016_10_10_12_50.csv Complete, status : 226 Transfer complete."
| rex field=raw_field "D:\\(.+\\)*(?<filename>.*)\.csv Complete, status : 226 Transfer complete.
I am extracting as below.
| makeresults
| eval raw_field="D:\Program Files\X620\ABC\TGF\Files\sss\Nsences_2016_10_10_12_50.csv Complete, status : 226 Transfer complete."
| rex field=raw_field "D:\\(.+\\)*(?<filename>.*)\.csv Complete, status : 226 Transfer complete."
| table raw_field filename
Please help me. Thanks in advance.
Dhirendra
1 Solution
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harsmarvania57
Ultra Champion
06-19-2019
12:50 AM
Hi,
Please try below regex.
<yourBaseSearch>
| rex field=<yourfield> "\x5c(?<filename>[^\x5c]+\.[^\s]+)"
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vinod94
Contributor
06-19-2019
01:18 AM
| makeresults
| eval date="D:\Program Files\X620\ABC\TGF\Files\sss\Nsences_2016_10_10_12_50.csv Complete, status : 226 Transfer complete."
| rex field=date "\\\Files.*\\\(?P<filename>.+)\s\w+,"
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dhirendra761
Contributor
06-19-2019
02:48 AM
Thank you for your answer @vinod94
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harsmarvania57
Ultra Champion
06-19-2019
12:50 AM
Hi,
Please try below regex.
<yourBaseSearch>
| rex field=<yourfield> "\x5c(?<filename>[^\x5c]+\.[^\s]+)"
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dhirendra761
Contributor
06-19-2019
02:48 AM
Thanks @harsmarvania57 for your answer 🙂
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harsmarvania57
Ultra Champion
06-19-2019
04:41 AM
Welcome 🙂
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