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Help to convert date using strftime

Marco_Develops
Path Finder

Currently I have a field holding a Julian date. I am trying to convert it using strftime but i'm having issues.

 

Date = 2022.091

Current query:

 

 

index = * | eval ConvertedDate = strftime(DATE,"%Y.%j")| table ConvertedDate

 

 

 

Ideally I would like to get an output like 04/03/2022

 

Thank you,

Marco

Labels (3)
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1 Solution

richgalloway
SplunkTrust
SplunkTrust

The strftime function converts an epoch timestamp (integer) into a human-readable string.  Use the strptime function to convert a datetime string into epoch form.

 

index = * 
| eval ConvertedDate = strftime(strptime(DATE,"%Y.%j"), "%m/%d/%Y")
| table ConvertedDate

 

 

---
If this reply helps you, Karma would be appreciated.

View solution in original post

richgalloway
SplunkTrust
SplunkTrust

The strftime function converts an epoch timestamp (integer) into a human-readable string.  Use the strptime function to convert a datetime string into epoch form.

 

index = * 
| eval ConvertedDate = strftime(strptime(DATE,"%Y.%j"), "%m/%d/%Y")
| table ConvertedDate

 

 

---
If this reply helps you, Karma would be appreciated.

Marco_Develops
Path Finder

@richgalloway This worked. Thank you for your time and explanation . 

-Marco

0 Karma
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