Splunk Search

count condition

subachu
New Member

I'm having trouble writing a search statement that sets the count to 0 when the service is normally.

This is my data example.

name status
A failed
B failed
C failed
A normally
B normally
C normally

Counting with name will also count normally.
I want to count status failed only.

In this case, everything is normally, I want to display 0.

I know this is not correct, but I want to do like this.

|eval A =if((status=failed),count,null)
|stats count as A

I can't think of a conditional statement that counts when the status is failed.

Tags (1)
0 Karma
1 Solution

mayurr98
Super Champion

Try this ?

 <your search> | stats count(eval(status="failed")) as failed_count by name

View solution in original post

mayurr98
Super Champion

Try this ?

 <your search> | stats count(eval(status="failed")) as failed_count by name

Sukisen1981
Champion

instead of if , use a case
|eval A=case(status=failed,1)
so A has counts only for failed status

0 Karma

subachu
New Member

Thank you for helping.
what do it mean (status=failed,1)?
I thought (status=failed,0).

0 Karma

Sukisen1981
Champion

hi you said 'I want to count status failed only.' hence I made status=failed as 0.
You can assign any value based on your need

0 Karma
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