Splunk Search

Replace Eval Function using Regex

Substance82
Path Finder

When using regex how can I take a field formatted as "0012-4250" and only show the 1st and lat 3 digits? I tried the following in which maintains the original output:

| eval AcctCode = replace(AcctCode,"(\d{4}-)(\d{4})","\1\2")
Labels (2)
Tags (1)
0 Karma
1 Solution

Substance82
Path Finder

Nevermind All.  

 

By some miracle I figured it out!

| eval ProdCode = replace(ProdCode,"^(\d)\d{3}-\d(\d{3})","\1xxx-x\2")

View solution in original post

Substance82
Path Finder

Nevermind All.  

 

By some miracle I figured it out!

| eval ProdCode = replace(ProdCode,"^(\d)\d{3}-\d(\d{3})","\1xxx-x\2")

richgalloway
SplunkTrust
SplunkTrust

The current regex takes the first 4 digits and the last 4 digits and then puts them back together, which is why the result does not change.  Try this, which takes the first and last 3 digits and puts them together.

| rex field=AcctCode mode=sed "s/(\d{3})\d-\d(\d{3})/\1\2/"

 

---
If this reply helps you, Karma would be appreciated.
0 Karma

Substance82
Path Finder

Hi. 

 

Your reply is greatly appreciated, but I must use the eval command to achieve my results. Do you have an eval command solution?

 

0 Karma
Get Updates on the Splunk Community!

App Platform's 2025 Year in Review: A Year of Innovation, Growth, and Community

As we step into 2026, it’s the perfect moment to reflect on what an extraordinary year 2025 was for the Splunk ...

Operationalizing Entity Risk Score with Enterprise Security 8.3+

Overview Enterprise Security 8.3 introduces a powerful new feature called “Entity Risk Scoring” (ERS) for ...

Unlock Database Monitoring with Splunk Observability Cloud

  In today’s fast-paced digital landscape, even minor database slowdowns can disrupt user experiences and ...