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How to compute the mean activity volume per field in Splunk?

Builder

How to Compute the mean activity volume per user in each hour yesterday, and find the ones more than n standard deviations above the mean?

Note: Considering user as a field

Any ideas about writing a search which satisfies the above condition?

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Re: How to compute the mean activity volume per field in Splunk?

Motivator

try something like this,,

base search | timechart span=1h mean(user) as mean, stdev(user) AS std | where std>10 AND mean>10

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Re: How to compute the mean activity volume per field in Splunk?

Path Finder

By mean activity, I am assuming you mean the average.
| stats avg(count) by date_hour, user

For standard deviation you can try something like below. Replace "n" with your amount.
| eventstats stdev(count) as deviation | eval outlier=deviation*"n" | where count > outlier

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