Splunk Search

How to compute the mean activity volume per field in Splunk?

pavanae
Builder

How to Compute the mean activity volume per user in each hour yesterday, and find the ones more than n standard deviations above the mean?

Note: Considering user as a field

Any ideas about writing a search which satisfies the above condition?

0 Karma
1 Solution

vasanthmss
Motivator

try something like this,,

base search | timechart span=1h mean(user) as mean, stdev(user) AS std | where std>10 AND mean>10

V

View solution in original post

mgrosholz
Path Finder

By mean activity, I am assuming you mean the average.
| stats avg(count) by date_hour, user

For standard deviation you can try something like below. Replace "n" with your amount.
| eventstats stdev(count) as deviation | eval outlier=deviation*"n" | where count > outlier

0 Karma

vasanthmss
Motivator

try something like this,,

base search | timechart span=1h mean(user) as mean, stdev(user) AS std | where std>10 AND mean>10

V
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