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How do divide greater than and less than in splunk?

sagar1905
New Member

I'm trying to divide my query into two parts, D>8000 as X and D<=8000 as Y, so i put it .... my search | eval count(if(D<=8000)) AS Y, count(if(D>8000)) AS X | transpose.................... but its not working. How do I divide it?

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1 Solution

micahkemp
Champion

The other answers look like they will accomplish what you want, but in terms of the syntax you started with I wonder if you're looking for this:

stats count(eval(D<=8000)) AS Y, count(eval(D>8000)) AS X

View solution in original post

0 Karma

micahkemp
Champion

The other answers look like they will accomplish what you want, but in terms of the syntax you started with I wonder if you're looking for this:

stats count(eval(D<=8000)) AS Y, count(eval(D>8000)) AS X
0 Karma

sagar1905
New Member

Thanks micahkemp, this works. So I should have used eval instead of if.

0 Karma

cmerriman
Super Champion

Do you want these as separate fields or as one field with two values?

To create one field with two values:

...| eval two_parts=if(D<=8000,”Y”,”X”)...

To get separate fields:

...|eval Y=if(D<=8000,D,null())|eval X=if(D>8000,D,null())...
0 Karma

mayurr98
Super Champion

Hey @sagar1905

Try this

.... my search | eval divide=case(D<=8000,”Y”,D>8000,”X”) | stats count by divide

Let me know if this helps!

0 Karma

sagar1905
New Member

Hey @mayurr98, it didn't work.
I got the following error
Error in 'eval' command: The expression is malformed. An unexpected character is reached at '”Y”,D>8000,”X”)'.

0 Karma

mayurr98
Super Champion

Try this
.... my search | eval divide=if(D<=8000,”Y”,”X”) | stats count by divide

0 Karma

richgalloway
SplunkTrust
SplunkTrust

What does "it's not working" mean? What do you get for X and Y?

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If this reply helps you, Karma would be appreciated.
0 Karma
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