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I have extracted a field from log files that is called file_Date and it is in the format "8/1/2017". How do get the day of the week from a date in this format. I CAN NOT use "_time" for when Splunk gets the date forwarded because it can be a different date based on the location of the server.
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Try this,
| eval tdate_w = strftime(strptime(file_Date, "%m/%d/%Y"), "%A") | table file_Date tdate_w
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If the _Date
is the same as _time
, then just use the field date_wday
.
If you need it in a number, then you can do a lookup
or case
.
If _Date
is not the same as _time
, then sbbadri's answer is probably what you want to consider.
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Try this,
| eval tdate_w = strftime(strptime(file_Date, "%m/%d/%Y"), "%A") | table file_Date tdate_w
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NOTE - If you prefer numbers, 0 for Sunday, 1 for Monday and so on, use "%w"
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This works perfectly! Thank you
