Time Segregation from Timestamp

[Jananee_iNautix]

Could you please let me know how to extract the day of the week, month,date(dd), time of the day (hh:mm:ss),year from the pattern : mm/dd/yy hh:mm:ss - 04/23/14 23:00:22
Eg of the result : Wednesday April 23 23:00:22 2014

[yannK]

The field "_time" contains the epoch time of the events, and is automatically displayed at search time on the local version of your time format and timezone.

If you want to create a new field with a different format, you can use the convert function.
see http://docs.splunk.com/Documentation/Splunk/6.0.3/SearchReference/Convert
and the formats http://docs.splunk.com/Documentation/Splunk/6.0.3/SearchReference/Commontimeformatvariables

<mysearch> | convert timeformat="%A %B %d %H:%M:%S %Y" ctime(_time) AS mytime | table mytime _time _raw

[somesoni2]

When Splunk indexes data it does some implicit field extractions like date_wday, date_month, date_mday, date_year etc.... You can form your expected output from there or you can use splunk command like convert or strftime to generate the output you need.