How to fetch time in Date format?

[aditsss]

Hi All,

I have one requirement .

I have one lookup in which there are two columns:

RunDateTime and Closed Time

RunDateTime -  2021-09-21 03:58:07

CLosedTime - 2019-01-08T14:50:36.000+0000

I need both RunDateTime and closedTime in below format:

RunDateTime- 2021-09-21

ClosedTime- 2019-01-08

query:

|inputlookup SDC.csv| table RunDateTime  ClosedTime

[bowesmana]

@aditsss 

Very simply, you can do

| inputlookup SDC.csv
| eval RunDateTime=substr(RunDateTime,1,10), ClosedTime=substr(ClosedTime,1,10)
| table RunDateTime  ClosedTime

which is just taking the first 10 characters of the string, as long as your data is well structures, i.e. leading zeros are used in days and months. 

[aditsss]

@bowesmana 

It was working for me previously . But I added one more column at the end of my lookup and after that I am getting rundatetime in the below Format.

Can you guide me on that:

rundatetime

12/30/2020

12/24/2020

12/2/2020

11/18/2020

11/17/2020

11/14/2020

10/27/2020

10/25/2020

10/20/2020

10/17/2020

10/16/2020

1/9/2021 3

1/8/2021 3

I want it in proper Date format. Can you guide me on that.

[bowesmana]

@aditsss 

| eval rundatetime=strftime(strptime(rundatetime,"%m/%d/%Y"), "%F")