Splunk Search

how to search a number which is 13 digits or more using regex in splunk?

Builder

Hi how can i find out a number which is 13 digits or more in a splunk search on index="xyz". Please let me know

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1 Solution

Splunk Employee
Splunk Employee
index=foo sourcetype=bar | rex "(?<long_number>\d{13,})"

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Motivator
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Esteemed Legend

Like this:

index=xyz | regex _raw = "\d{13,}"

Splunk Employee
Splunk Employee
index=foo sourcetype=bar | rex "(?<long_number>\d{13,})"

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Motivator

You might add max_match=0 to the rex command

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Splunk Employee
Splunk Employee

@Landen998 Why

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Motivator

The event may have more than one series of 13 digit numbers. The 13 digit number of interest may not be the first one it finds in the event. The event may not have separated correctly. Any other reason.

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Builder

So what could be the final search query to display those digits?

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Motivator

Either

index=foo sourcetype=bar | rex max_match=0 "(?<long_number>\d{13,})"

OR

index=xyz | regex _raw = "\d{13,}"

from Woodcock's answer below. All depends on what you want to do. Extract the number (above) or filter events for the number but not extract it (below). .. or you could do both:

index=foo sourcetype=bar | rex max_match=0 "(?<long_number>\d{13,})" | search long_number=*
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Builder

Thanks it worked

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