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extract names from URL using regex

anooshac
Path Finder

Hello all,

I haven't used rex many times.

I have a URL like this, http;s://ab-abcd.in.xyz.com/abcd_xyz/job/example_name/" .

Here ab-abcd.in.xyz.com is server name, abcd_xyz is project name and example_name is task name.

I have to extract these using regex. I have tried using this query,

|rex field=URL "https:\//(?<server_name>\w*)/\(?<project_name>\w*)\/job\/(?<task_name>\w*)\/"| table server_name project_name task_name

I know that this query is wrong.But confused on how to correct it.  Can anyone help me to correct this query.

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1 Solution

bowesmana
SplunkTrust
SplunkTrust

Try this

| rex field=URL "https://(?<server_name>[^/]*)/(?<project_name>[^/]*)/job/(?<task_name>[^/]*)" 

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0 Karma

bowesmana
SplunkTrust
SplunkTrust

Try this

| rex field=URL "https://(?<server_name>[^/]*)/(?<project_name>[^/]*)/job/(?<task_name>[^/]*)" 

View solution in original post

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