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jip31
Motivator
03-11-2019
04:09 AM
Hello
I use the eval below in order to calculate a percentage
| eval Trend_Proc_time=round(100-(Proc_dest*100)/(Proc_source),1)." %"
When Proc_dest is > to Proc_source I have a result with minus - perfect
But when Proc_dest is < to Proc_source, I need to have a + sign before the result
could you help me to do this please?
1 Solution
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nickhills
Ultra Champion
03-11-2019
04:34 AM
Hi.
Using regex/sed you could try this
...| eval Trend_Proc_time=round(100-(Proc_dest*100)/(Proc_source),1)." %"
|rex mode=sed field=Trend_Proc_time "s/^(\d+)/+\1/"
If my comment helps, please give it a thumbs up!
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nickhills
Ultra Champion
03-11-2019
04:34 AM
Hi.
Using regex/sed you could try this
...| eval Trend_Proc_time=round(100-(Proc_dest*100)/(Proc_source),1)." %"
|rex mode=sed field=Trend_Proc_time "s/^(\d+)/+\1/"
If my comment helps, please give it a thumbs up!
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jip31
Motivator
03-11-2019
05:21 AM
perfect thanks
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vnravikumar
Champion
03-11-2019
04:21 AM
Hi
Try like
your query| eval Trend_Proc_time=round(100-(Proc_dest*100)/(Proc_source),1)
| eval Trend_Proc_time=if(Trend_Proc_time>0,"+".Trend_Proc_time." %",Trend_Proc_time." %")
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jip31
Motivator
03-11-2019
05:21 AM
sorry it doesnt works
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