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How to replace string using rex with partial matched string?

LearningGuy
Builder

How to replace string using rex with partial matched string?
Thank you for your help.
For example:
I tried to replace "::" (double colon) with ":0:"  (colon zero colon) if it the previous characters contain ":" followed by "1 to 3 characters" 
| rex mode=sed field=ip "s/:.{1,3}::/:.{1,3}:0:/g"   => this does not work because it will literally replace it with
":.{1,3}:0:"   instead of retaining the matched strings

Before
a0:1::21
b0:1c::21
c0:a13::23

After
a0:1:0:21
b0:11:0:21
c0:111:0:23

Labels (1)
0 Karma
1 Solution

richgalloway
SplunkTrust
SplunkTrust

Characters to be retained should be enclosed in a capture group and that group referenced in the replacement text.

| rex mode=sed field=ip "s/:(.{1,3})::/:\1:0:/g" 
---
If this reply helps you, Karma would be appreciated.

View solution in original post

LearningGuy
Builder

It worked!!  Thank you..    

richgalloway
SplunkTrust
SplunkTrust

Characters to be retained should be enclosed in a capture group and that group referenced in the replacement text.

| rex mode=sed field=ip "s/:(.{1,3})::/:\1:0:/g" 
---
If this reply helps you, Karma would be appreciated.
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