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How do you make a regex expression to capture everything after the timestamp?

MikaJustasACN
Path Finder

Hello,

Cannot crack this one. I have the following event:

Fri Oct 26 07:19:41 2018
STATS: GATHER_STATS_JOB encountered errors. Check the trace file.
Errors in file G:\lumpy\bumpy\ykt\ttee\hee\trace.trc:

Code: timeout occurred

This an example event, and it does not have the exact character matches or exact number of lines, so basically I need to pick everything after the year \d{4}. Even If I set to ignore the line new line, it always extracts only the first line after the timestamp, but never all the lines. In regex101 it works fine.

rex I am using: | rex field=_raw "\n(?(.|\n)*)"

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0 Karma
1 Solution

MikaJustasACN
Path Finder

The following rex did the trick. it was not new line \n but some other stuff (one or several of [\r\n\t\f\v ] )

\d{2}\s\d{2}:\d{2}:\d{2}\s\d{4}\s(?(.+|\s)*)

If anyone sees how this can be improved, would be great 🙂

View solution in original post

0 Karma

renjith_nair
Legend

@MikaJustasACN ,

Try this in splunk,

rex field=_raw "\d{4}(?<MY_FIELD>(.|\s)*)"

Extract everything after the "year" field

Happy Splunking!

MikaJustasACN
Path Finder

The following rex did the trick. it was not new line \n but some other stuff (one or several of [\r\n\t\f\v ] )

\d{2}\s\d{2}:\d{2}:\d{2}\s\d{4}\s(?(.+|\s)*)

If anyone sees how this can be improved, would be great 🙂

0 Karma
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