Splunk Search

Extracting numbers between words

ibekacyril
Explorer

Say I have this data:

c.i.m This is just a sample 23456 Yes it is true.

My question is how do I extract 23456 and pass it to a new field since there is no key-value pair in this scenario? I would also want to do a count on the new field.

Thanks and please I would not mind some explanation on your code too.

0 Karma
1 Solution

MuS
SplunkTrust
SplunkTrust

Hi ibekacyril,

Well, the straight approach is to get only digits matching in the regex

(?<my_number>\d+)

This will create a field called my_number and you can run a stats count(my_number) on it 😉

Next example is this one:

\w+\s(?<my_number>[^\s]+)\s

That's faster but will match This and you want the numbers ... so on to the next one

(?:\w\s)+(?<my_number>\d+)\s

a non-captureing group of one and unlimited times, as many times as possible, giving back as needed [greedy]
\w match any word character [a-zA-Z0-9_] \s match any white space character [\r\n\t\f ]
but this will be slower because it will need more steps to match the result you want - Hint: www.regex101.com

c\.i\.m\sThis\sis\sjust\sa\ssample\s(?<my_number>\d+)\s

almost as fast as the first one, but it take a bit more steps to match

There almost endless possibilities for regex to match, but you want the most efficient one - use regex101.com and learn how to use regex 😉

Hope this helps ...

cheers, MuS

View solution in original post

MuS
SplunkTrust
SplunkTrust

Hi ibekacyril,

Well, the straight approach is to get only digits matching in the regex

(?<my_number>\d+)

This will create a field called my_number and you can run a stats count(my_number) on it 😉

Next example is this one:

\w+\s(?<my_number>[^\s]+)\s

That's faster but will match This and you want the numbers ... so on to the next one

(?:\w\s)+(?<my_number>\d+)\s

a non-captureing group of one and unlimited times, as many times as possible, giving back as needed [greedy]
\w match any word character [a-zA-Z0-9_] \s match any white space character [\r\n\t\f ]
but this will be slower because it will need more steps to match the result you want - Hint: www.regex101.com

c\.i\.m\sThis\sis\sjust\sa\ssample\s(?<my_number>\d+)\s

almost as fast as the first one, but it take a bit more steps to match

There almost endless possibilities for regex to match, but you want the most efficient one - use regex101.com and learn how to use regex 😉

Hope this helps ...

cheers, MuS

ibekacyril
Explorer

Thank you so much, especially with the regex101.com. The steps you gave equally helped.

0 Karma
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