Extracting fields using regex

[kailun92]

When i try to extract a field using this (?i)humidity : (?P.+) expression. The result below is given. Is there anyway to extract just 0.82 which is the humidity I needed ? Need help on this, thanks in advance 😃

0.82
icon : cloudy
ozone : 263.15
precipIntensity : 0.001
precipProbability : 0.05
precipType : rain
pressure : 1005.57
summary : Dry and Overcast
temperature : 80.94

[chris · Accepted solution]

How about:

(?i)humidity : (?P<fieldname>[\d\.]+)

[kailun92]

Check you with you, do you know how to extract summary : Dry and Overcast ? Same situation. If cannot then how about icon ? how to extract the words out ? I am extraction the part below it also.

[kailun92]

Thank you SO MUCH, i love you i have been solving for so long