Getting Data In

Time Format conversion using strptime

asarolkar
Builder

I have a date timestamp coming in as a string in this format
2012-08-08 11:29:03.727000000

This is extracted as a field called createDtTimeStamp

I want to simply extract JUST the date part from this field and use the following query:

... | eval createDt = strftime( strptime( createDtTimeStamp, "%b %d %H:%M:%S" ), "%m/%d/%Y %p")

This does not seem to work. Any ideas why ?

1 Solution

Ayn
Legend

Well your format string seems to be off. %b is "Locale’s abbreviated month name." which does not match 2012-08-08. You'll likely want something like

... | eval createDt = strftime(strptime(createDtTimeStamp,"%Y-%m-%d %H:%M:%S"),"%m/%d/%Y %p")

View solution in original post

Ayn
Legend

Well your format string seems to be off. %b is "Locale’s abbreviated month name." which does not match 2012-08-08. You'll likely want something like

... | eval createDt = strftime(strptime(createDtTimeStamp,"%Y-%m-%d %H:%M:%S"),"%m/%d/%Y %p")

asarolkar
Builder

worked like a charm !

0 Karma
Get Updates on the Splunk Community!

The Payment Operations Wake-Up Call: Why Financial Institutions Can't Afford ...

The same scenario plays out across financial institutions daily. A payment system fails at 11:30 AM on a busy ...

Make Your Case: A Ready-to-Send Letter for Getting Approval to Attend .conf25

Hello Splunkers, Want to attend .conf25 in Boston this year but not sure how to convince your manager? We've ...

Community Spotlight: A Splunk Expert's Journey

In the world of data analytics, some journeys leave a lasting impact not only on the individual but on the ...