Splunk Search

max values from two weeks using timechart

secure
Path Finder

Hello Everyone,

i have a dataset where I'm generating a column of number of servers per day.  using a timechart command for last 2 weeks.
earliest="-14d" latest=now() index=*...... | timechart span=1d dc(hostname) as servercount

My requirement is to split the data in previous week and latest week and get the maximum count from the previous week and the latest week 

 

Labels (1)
Tags (1)
0 Karma

gcusello
SplunkTrust
SplunkTrust

Hi @secure ,

did yu tried to use a different span period?

earliest="-14d" latest=now() index=*...... 
| timechart span=1w dc(hostname) AS servercount

Ciao.

Giuseppe

0 Karma

PickleRick
SplunkTrust
SplunkTrust

@gcuselloThat's something different. You're calculating weekly count of distict values whereas, as I understand, @secure wants to have maximum value of daily distinct count per week.

There are several possible approaches here.

One is to use the timechart output and use timewrap to transform the output into separate weekly data series. Since timewrap is a relatively straightforward command I'll leave the actual search to the reader 😉

Another way is to do manual binning

<@secure's search>
| bin _time span=1w as weekno
| stats max(servercount) by weekno
Get Updates on the Splunk Community!

Building Reliable Asset and Identity Frameworks in Splunk ES

 Accurate asset and identity resolution is the backbone of security operations. Without it, alerts are ...

Cloud Monitoring Console - Unlocking Greater Visibility in SVC Usage Reporting

For Splunk Cloud customers, understanding and optimizing Splunk Virtual Compute (SVC) usage and resource ...

Automatic Discovery Part 3: Practical Use Cases

If you’ve enabled Automatic Discovery in your install of the Splunk Distribution of the OpenTelemetry ...