Tricky regex

[dbcase]

Hi,

I have this data
"166.78.66.241" 70.121.107.109 "70.121.107.109" - - [19/Jan/2018:12:24:33 -0600] "POST /fileUpload/image HTTP/1.1" 200 - 137895 214 UCT-556540 "-" "-" "-"

10.210.192.15 - - [19/Jan/2018:11:00:22 -0500] "POST /fileUpload/image HTTP/1.1" 200 - "-" "-"

27.127.175.202, 192.168.10.101 - - [19/Jan/2018:08:59:53 +0900] "POST /fileUpload/image HTTP/1.1" 200 - "-" "-"

and I need to extract out the IP addresses

The first line IP address would be 70.121.107.109
The second line IP address would be 10.210.192.15
and the third line would be 27.127.175.202

I've tried and failed several times to figure out how to get 1 regex expression
to do this

any thoughts?

[micahkemp · Accepted solution]

It looks like you want the first non-quotes IP address, which should be doable with this:

https://regex101.com/r/Kv2miD/1

(?<ip>(?:[0-9]{1,3}\.){3}[0-9]{1,3})[\s,]

That just looks for something that looks like an IP address followed immediately by a whitespace or comma.

[dbcase]

Wow, just wow.... One day I want to grow up and do regex like that! 🙂

Many thanks!!