RegEx for the free -m command - Linux

[aferone]

I have a script that runs the "free -m" command, and I am only pulling (grepping) the lines like the following:

-/+ buffers/cache:        219       1789
-/+ buffers/cache:       1469      10557

The first value is used memory, and the second value is free memory.

The RegEx for free memory works for all of the logs:

(?i)^[^:]*:\s+\d+\s+(?P<FreeMemory>.+)

However, for used memory, the following RegEx only works for the 2nd log line above, because of the amount of spaces between "cache:" and the value.

(?i)/cache:       (?P<UsedMemory>[^ ]+)

How do I get the RegEx to work, regardless of how many spaces are in between?

Thanks!

[gfuente · Accepted solution]

Hello

Use this regex to extract both values at the same time:

... | rex "\:\s+(?<usedmemory>\d+)\s+(?<freememory>\d+)" | ...

Regards

[aferone]

Perfect!! Thank you!