Hi ! I am trying to display a timechart that gives the data of a week, and the data of the same week but one year earlier.
I have done something with timechart and timewrap that gives me that comparison, but also gives me the comparison of all the rest of the year. How can I just isolate a specific week ? Thanks !
My current request :
index="sales_2017" OR index="sales_2018"
| timechart span=d count
| timewrap y
What I got :
What I would like to have :
If you know the week number in the year you can try this:
index="sales_2017" OR index="sales_2018"
| eval date_week_of_year = strftime(_time, "%U")
| where date_week_of_year = "<week you are after>"
| timechart span=d count
| timewrap w
If you know the week number in the year you can try this:
index="sales_2017" OR index="sales_2018"
| eval date_week_of_year = strftime(_time, "%U")
| where date_week_of_year = "<week you are after>"
| timechart span=d count
| timewrap w
I think the week numbers are different from one year to the other in my case so it doesn't work
You said you want "the data of a week, and the data of the same week but one year earlier"
For a moment forget about splunk. how do you accomplish this on paper, if not looking at the week number in the year? If i recall correctly all years have 52 weeks. This doesn't change regardless of the year. What does change is the day of the week a year starts.
This | eval date_week_of_year = strftime(_time, "%U")
takes that in consideration by giving you the number of the week starting on Sunday and considering all theother days before the 1st Sunday as week 0.
If you want your week to start on monday you can switch %U to %W in this expression.