Hello Splunk Lovers! i have date format 202211131614220000 and i want convert this format to readble for Splunk
i should use strptime and strftime, but i have some problems. Please, give me prompt
@splunk_enjoyer You need to state your question clearly. "Have problems" is not a question. What is the definition of "readable for Splunk"? Splunk only understands epoch, so strptime is your answer. The string you illustrated looks like some combination of 4-digit year followed by some representation of month, day, hour, etc. Such may be obvious to you. But unless you can tell others what exact format it really is, others can only speculate like @inventsekar did. If you actually mean "readable by humans," and you don't care whether Splunk can use it to perform calculations based on epoch, you can use string manipulation to do so, e.g., you can do something as crazy as
| eval readable_time = replace(timestamp, "^(\d{4})(\d{2})(\d{2})(\d{2})(\d{2})(\d{2})(\d+)", "\1-\2-\3T\4:\5:\6.\7-00:00")
provided the format is 4-digit year, 2-digit month, 2-digit day, 2-digit hour, 2-digit minute, 2-digit second, 4-digit subsecond (like @inventsekar speculated), and the desired output format is something resembling ISO with Zulu time zone. Remember, it is unfair to make volunteers read your mind. Make your question as clear as possible.
Hi @splunk_enjoyer ..
Please check this:
| makeresults | eval timestamp="202211131614220000"
| eval goodtimestamp = strftime(strptime(timestamp,"%Y%m%d%H%M%S%4Q"),"%m/%d/%Y %H:%M:%S")
|table timestamp goodtimestamp
its works! thanks man!
sorry, i had some problems, take your karma. thanks a lot!