Splunk Search

How to convert an IP address to binary?

Applegreengrape
Explorer

I need to convert an IP address to binary.

i.e. IP Address:10.171.230.151
-->10 171 230 151
-->11000000101010000000010100000000
finally it is a 32 digit binary

How can I do it with a Splunk search?

thanks

Tags (4)
1 Solution

javiergn
Super Champion

Hi,

Shouldn't 10.171.230.151 be represented in binary as

00001010 . 10101011 . 11100110 . 10010111

In any case, if that is what you are trying to achieve, see if the following code helps:

| stats count
| fields - count
| eval IP = "10.171.230.151"
| eval octet = split(IP, ".")
| eval rank = split("1,2,3,4", ",")
| eval octet_rank = mvzip(rank, octet)
| fields - octet, rank
| mvexpand octet_rank
| eval octet_rank_split = split(octet_rank, ",")
| eval rank = mvindex(octet_rank_split, 0)
| eval octet = mvindex(octet_rank_split, 1)
| fields - octet_rank, octet_rank_split
| eval power = mvrange(0,8)
| mvexpand power
| eval base2 = pow(2, power)
| eval mydiv = floor(octet / base2)
| eval octet_bin = mydiv % 2
| fields - mydiv, base2
| sort limit=0 IP, rank, octet, - power
| stats list(octet_bin) as octet_bin by IP, rank, octet
| eval octet_bin = mvjoin(octet_bin, "")
| sort limit=0 IP, rank
| stats list(octet_bin) as octet_bin by IP
| eval octet_bin = mvjoin(octet_bin, ".")

Output:

IP  octet_bin
10.171.230.151  00001010.10101011.11100110.10010111 

I did answer something similar in the past in case that helps too:

https://answers.splunk.com/answers/342277/is-it-possible-to-perform-bitwise-operations-on-va.html

Thanks,
J

View solution in original post

javiergn
Super Champion

Hi,

Shouldn't 10.171.230.151 be represented in binary as

00001010 . 10101011 . 11100110 . 10010111

In any case, if that is what you are trying to achieve, see if the following code helps:

| stats count
| fields - count
| eval IP = "10.171.230.151"
| eval octet = split(IP, ".")
| eval rank = split("1,2,3,4", ",")
| eval octet_rank = mvzip(rank, octet)
| fields - octet, rank
| mvexpand octet_rank
| eval octet_rank_split = split(octet_rank, ",")
| eval rank = mvindex(octet_rank_split, 0)
| eval octet = mvindex(octet_rank_split, 1)
| fields - octet_rank, octet_rank_split
| eval power = mvrange(0,8)
| mvexpand power
| eval base2 = pow(2, power)
| eval mydiv = floor(octet / base2)
| eval octet_bin = mydiv % 2
| fields - mydiv, base2
| sort limit=0 IP, rank, octet, - power
| stats list(octet_bin) as octet_bin by IP, rank, octet
| eval octet_bin = mvjoin(octet_bin, "")
| sort limit=0 IP, rank
| stats list(octet_bin) as octet_bin by IP
| eval octet_bin = mvjoin(octet_bin, ".")

Output:

IP  octet_bin
10.171.230.151  00001010.10101011.11100110.10010111 

I did answer something similar in the past in case that helps too:

https://answers.splunk.com/answers/342277/is-it-possible-to-perform-bitwise-operations-on-va.html

Thanks,
J

Applegreengrape
Explorer

wow good stuff! I will definitely try it! thannnnnks!
≧❂◡❂≦

0 Karma
Get Updates on the Splunk Community!

Accelerating Observability as Code with the Splunk AI Assistant

We’ve seen in previous posts what Observability as Code (OaC) is and how it’s now essential for managing ...

Integrating Splunk Search API and Quarto to Create Reproducible Investigation ...

 Splunk is More Than Just the Web Console For Digital Forensics and Incident Response (DFIR) practitioners, ...

Congratulations to the 2025-2026 SplunkTrust!

Hello, Splunk Community! We are beyond thrilled to announce our newest group of SplunkTrust members!  The ...