Splunk Dev

How do I extract filename from different paths in the field name "FileList" with the help of regex ?

jugalkinariwala
Explorer

I have below files in one of the fields named "FileList"
/dir1/dir2/f1.txt

/dir1/f2.csv

/dir1/dir2/dir3/xyzdir/f3.bat

f4.txt

/xvz/dir/f5.txt

I want an output which shows only the last name which is the actual filename from the above "FileList" field as below
f1.txt

f2.csv

f3.bat

f4.txt

f5.txt

0 Karma
1 Solution

jugalkinariwala
Explorer

Got the results myself .

 

Thanks to all 🙂

View solution in original post

0 Karma

jugalkinariwala
Explorer

Got the results myself .

 

Thanks to all 🙂

0 Karma
Get Updates on the Splunk Community!

Building Reliable Asset and Identity Frameworks in Splunk ES

 Accurate asset and identity resolution is the backbone of security operations. Without it, alerts are ...

Cloud Monitoring Console - Unlocking Greater Visibility in SVC Usage Reporting

For Splunk Cloud customers, understanding and optimizing Splunk Virtual Compute (SVC) usage and resource ...

Automatic Discovery Part 3: Practical Use Cases

If you’ve enabled Automatic Discovery in your install of the Splunk Distribution of the OpenTelemetry ...