Security

How to extract complete string using regular expression

Nith1
Path Finder

Hi TEam

I have the below data in the logs how can i extract the complete string using regular expression . 

4678-business-release-${table.date}-292_(2) 
6789-business-release-06102021-292

I have tried using 

| rex field=_raw "deploy_release\=(?<Deploy_Release>.[^\n][a-z0-9#][^\n])" 

But i could get only the first values (i.e) 4678 and 6789 but not the completed string .Can someone please correct me 

Thanks

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0 Karma

kamlesh_vaghela
SplunkTrust
SplunkTrust

@Nith1 

Can you please share your expected OP from you sample event?

Meanwhile can you please try this?

| rex field=_raw "deploy_release\=(?<Deploy_Release>.[^\n].*)"

 

Thanks
KV
▄︻̷̿┻̿═━一

If any of my reply helps you to solve the problem Or gain knowledge, an upvote would be appreciated. 

0 Karma

ITWhisperer
SplunkTrust
SplunkTrust
| rex field=_raw "deploy_release\=(?<Deploy_Release>.*?)" 

Can you share the full event as you might be able to do this a different way if the deploy_release field is not the remainder of the line and is delimited by a space for example

| rex field=_raw "deploy_release\=(?<Deploy_Release>[^\s]+)" 
0 Karma
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