Developing for Splunk Enterprise

Can I get the current app from Python?

Path Finder

I notice there is a method to get the current apps dir from python. There is also a getCurrentApp() available in javascript, but I need the current app from Python.

Does anyone have any suggestions?

Tags (2)
1 Solution

Splunk Employee
Splunk Employee

Which type of python file? We tend to use python's __file__ attribute. I assume that you have imported os and cherrypy at least.

For example, in the file $SPLUNK_HOME/etc/apps/TA-opseclea/appserver/controllers/:

 app_name = __file__.split('.')[-2]

If I was implementing a controller method where a request was routed to me:

@route('/:app/:action=edit/:name')
@expose_page(must_login=True, methods=['GET']) 
def edit(self, app, action, name, **kwargs):
    host_app = cherrypy.request.path_info.split('/')[3]

For a scripted input in an app's .\bin directory:

app_name = __file__.split(os.sep)[-3]

View solution in original post

0 Karma

Splunk Employee
Splunk Employee

Which type of python file? We tend to use python's __file__ attribute. I assume that you have imported os and cherrypy at least.

For example, in the file $SPLUNK_HOME/etc/apps/TA-opseclea/appserver/controllers/:

 app_name = __file__.split('.')[-2]

If I was implementing a controller method where a request was routed to me:

@route('/:app/:action=edit/:name')
@expose_page(must_login=True, methods=['GET']) 
def edit(self, app, action, name, **kwargs):
    host_app = cherrypy.request.path_info.split('/')[3]

For a scripted input in an app's .\bin directory:

app_name = __file__.split(os.sep)[-3]

View solution in original post

0 Karma

Path Finder

I am writing a custom search command. Looks like the last option you presented may be the one. I will give it a shot. Thanks

0 Karma
State of Splunk Careers

Access the Splunk Careers Report to see real data that shows how Splunk mastery increases your value and job satisfaction.

Find out what your skills are worth!