Splunk Search

How to Evaluate a field from the list of another search and create a table

manorajk
Engager

There are two queries

`query 1` will give ID, TIME fields

`query 2` will give list of SPECIAL_ID

I want to create a table with TIME, ID, IS_SPECIAL_ID

IS_SPECIAL_ID is evaluated to true/false based on the condition where is ID is part of the list SPECIAL_ID

 

Labels (1)
0 Karma
1 Solution

ITWhisperer
SplunkTrust
SplunkTrust

Simplistically, you could do something like this

`query 1`
| join type=outer ID
  [search `query 2`
   | dedup SPECIAL_ID
   | rename SPECIAL_ID as ID
   | eval IS_SPECIAL_ID="true"]
| fillnull value="false" IS_SPECIAL_ID

However, as has been mentioned in numerous posts, using join and subsearches is not  always best practice due to the limitations of subsearches, but if the above suffices, it is a simple approach.

View solution in original post

manorajk
Engager

@ITWhisperer Really appreciate your help here.

0 Karma

ITWhisperer
SplunkTrust
SplunkTrust

Simplistically, you could do something like this

`query 1`
| join type=outer ID
  [search `query 2`
   | dedup SPECIAL_ID
   | rename SPECIAL_ID as ID
   | eval IS_SPECIAL_ID="true"]
| fillnull value="false" IS_SPECIAL_ID

However, as has been mentioned in numerous posts, using join and subsearches is not  always best practice due to the limitations of subsearches, but if the above suffices, it is a simple approach.

Get Updates on the Splunk Community!

Prove Your Splunk Prowess at .conf25—No Prereqs Required!

Your Next Big Security Credential: No Prerequisites Needed We know you’ve got the skills, and now, earning the ...

Splunk Observability Cloud's AI Assistant in Action Series: Observability as Code

This is the sixth post in the Splunk Observability Cloud’s AI Assistant in Action series that digs into how to ...

Splunk Answers Content Calendar, July Edition I

Hello Community! Welcome to another month of Community Content Calendar series! For the month of July, we will ...