Splunk Search

How to Convert time format?

Edwin1471
Path Finder

Hi,  

 i need to write a query that converts time format from  

Edwin1471_0-1657631341827.png minutes to  format Xh Xmin Xs

my query

| eval finish_time_epoch = strftime(strptime(FINISH_TIME, "%Y-%m-%d %H:%M:%S"),"%Y-%m-%d %H:%M:%S")
| eval start_time_epoch = strftime(strptime(START_TIME, "%Y-%m-%d %H:%M:%S"),"%Y-%m-%d %H:%M:%S")
| eval duration_s = strptime(FINISH_TIME, "%Y-%m-%d %H:%M:%S") - strptime(START_TIME, "%Y-%m-%d %H:%M:%S")
| eval duration_min = round(duration_s / 60, 2)
| chart sum(duration_min) as "time" by Yd_count_data

 

 

 

Labels (2)
0 Karma
1 Solution

gcusello
SplunkTrust
SplunkTrust

Hi @Edwin1471,

if "time" is the duration expressed in minutes, you have to add at the end of your search an eval statement like the following:

|  eval
   time_hours=round(time/60,0),
   time_min=round(time-time_hours*60,0),
   time_sec=round((time-time_hours*60-time_min)*60,0)
| eval time=time_hours." h ".time_min." m ".time_sec

Ciao.

Giuseppe

View solution in original post

gcusello
SplunkTrust
SplunkTrust

Hi @Edwin1471,

if "time" is the duration expressed in minutes, you have to add at the end of your search an eval statement like the following:

|  eval
   time_hours=round(time/60,0),
   time_min=round(time-time_hours*60,0),
   time_sec=round((time-time_hours*60-time_min)*60,0)
| eval time=time_hours." h ".time_min." m ".time_sec

Ciao.

Giuseppe

Get Updates on the Splunk Community!

Introducing the 2024 SplunkTrust!

Hello, Splunk Community! We are beyond thrilled to announce our newest group of SplunkTrust members!  The ...

Introducing the 2024 Splunk MVPs!

We are excited to announce the 2024 cohort of the Splunk MVP program. Splunk MVPs are passionate members of ...

Splunk Custom Visualizations App End of Life

The Splunk Custom Visualizations apps End of Life for SimpleXML will reach end of support on Dec 21, 2024, ...