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Help with regex - How to exclude multiple parentheses and slashes from a field?

jalo23
Explorer

Is there a more elegant way to do this? New to using rex & I can’t seem to strip out the multiple parentheses and slashes from a field without using replace.  (I don't have control over the data, I know it is better to strip it out first.) These do work but in some cases there are more parentheses and slashes - is there a way to strip all of them out at once, or do I need to make repeating phrases?

| rex mode=sed field=Field_A "s/\(\)/ /g"

| rex mode=sed field=Field_B "s/\(\)/ /g"

| rex mode=sed field=Field_B "s/\// /g"

Labels (3)
0 Karma
1 Solution

richgalloway
SplunkTrust
SplunkTrust

You can combine the parentheses and slash into a character class to strip them all out at once.  You will, however, need a separate rex command for each field being processed.

| rex mode=sed field=Field_A "s;[\(\)/];;g"

| rex mode=sed field=Field_B "s;[\(\)/];;g"
---
If this reply helps you, Karma would be appreciated.

View solution in original post

richgalloway
SplunkTrust
SplunkTrust

You can combine the parentheses and slash into a character class to strip them all out at once.  You will, however, need a separate rex command for each field being processed.

| rex mode=sed field=Field_A "s;[\(\)/];;g"

| rex mode=sed field=Field_B "s;[\(\)/];;g"
---
If this reply helps you, Karma would be appreciated.

jalo23
Explorer

That worked great, thank you!

| rex mode=sed field=Field_A "s;[\(\)/];;g"
| rex mode=sed field=Field_A "s;[\(\)/];;g"
| rex mode=sed field=Field_A "s/\(\)/ /g"
| rex mode=sed field=Field_A "s/\// /g"
| rex mode=sed field=Field_A "s/\// /g"

0 Karma
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