Deployment Architecture

Increasing Replication and Search Factor

shrutheen
Explorer

I have 3 Search Heads and 3 Indexers with Replication Factor =1 and Search Factor=1. My requirement is to increase this to RF=3 and SF=2

Each indexer has around 800GB of data.

Now if I increase the replication factor to 3 does it mean each indexer will end up with around 2.4TB of data post data rebalancing.

And what would be the approximate data size in each indexer if RF is set to 2.

Labels (1)
0 Karma

gcusello
SplunkTrust
SplunkTrust

Hi @shrutheen,

The question is: I suppose that you have an Indexer Cluster, so why have you RF=1?

Anyway, I think that having 800 GB with RF=1 and SF=1 you shouldn't have 2400 GB with RF=3 and SR=2 because the tsindexes (SF) take around the 35% of the space required, so you should have for 100GB/day:

total row data = 100GB * 15% * RF = 45GB
tsindexes data = 100GB * 35% * SF = 70GB
total storage = 115GB
peer storage =total / 3 = 38.3GB

So what's the daily indexed logs of your infrastructure?

For this job is usually requested  at least a Splunk Architect, this isn't a job for the Community.

Ciao.

Giuseppe

0 Karma
Get Updates on the Splunk Community!

Introducing the 2024 SplunkTrust!

Hello, Splunk Community! We are beyond thrilled to announce our newest group of SplunkTrust members!  The ...

Introducing the 2024 Splunk MVPs!

We are excited to announce the 2024 cohort of the Splunk MVP program. Splunk MVPs are passionate members of ...

Splunk Custom Visualizations App End of Life

The Splunk Custom Visualizations apps End of Life for SimpleXML will reach end of support on Dec 21, 2024, ...