topic Re: How to remove part of the string using rex in Getting Data In

How to remove part of the string using rex

aaa2324 — Mon, 03 May 2021 05:22:51 GMT

I have the below string and would like to remove the date and time part, please help with the query

*abc -04/30, 08:14:07 - c

Re: How to remove part of the string using rex

ITWhisperer — Mon, 03 May 2021 05:56:40 GMT

| makeresults | eval _raw="abc -04/30, 08:14:07 - c" | rex mode=sed "s/\-\d\d\/\d\d,\s\d\d:\d\d:\d\d\s/- /g"

Re: How to remove part of the string using rex

aaa2324 — Mon, 03 May 2021 08:18:08 GMT

Thanks however not getting the desired results, if the date and time are dynamic and keeps changing then please help with the complete query. I want to remove the date and time completely and show the results

abc -04/30, 08:14:07 - c

abc -04/28, 08:15:06 - c

abc -04/29, 08:12:09 - a

Re: How to remove part of the string using rex

ITWhisperer — Mon, 03 May 2021 08:35:32 GMT

Please explain how the suggested rex does not do as you expected. It might be clearer if you provide some real anonymised events with which to work with.

Re: How to remove part of the string using rex

aaa2324 — Mon, 03 May 2021 08:59:21 GMT

Sorry if the question was not clear.

my intention is to remove date and time fields from the below set of input.

let’s say the column xyz has below contents

abc -04/30, 08:14:07 - c

abc -04/28, 08:15:06 - c

abc -04/29, 08:12:09 - a

my result should be something like below only remove the date and time and display rest of the fields

abc - - c

abc - - a

Re: How to remove part of the string using rex

ITWhisperer — Mon, 03 May 2021 09:12:20 GMT

| makeresults | eval xyz="abc -04/30, 08:14:07 - c abc -04/28, 08:15:06 - c abc -04/29, 08:12:09 - a" | rex field=xyz max_match=0 "(?<xyz>.*)\n*" | mvexpand xyz | rex mode=sed field=xyz "s/\-\d\d\/\d\d,\s\d\d:\d\d:\d\d\s/- /g"