topic Re: unable to pass URL using curl command in Getting Data In

unable to pass URL using curl command

anooshac — Tue, 08 Feb 2022 06:43:04 GMT

Hi all,

I am passing some data in JSON format to Splunk using curl. When i try to pass the URL it gives an error " nested brace in URL position 19". Not getting where went wrong even though all the braces are proper. Can anyone help me in this?

Re: unable to pass URL using curl command

PickleRick — Tue, 08 Feb 2022 07:18:30 GMT

Well, something must be wrong if you're getting an error. We can't know what it is without more details about your curl invocation.

Re: unable to pass URL using curl command

anooshac — Tue, 08 Feb 2022 08:03:02 GMT

I am using the following to add data. I am not supposed to share the data here so i have given one example.

curl https://aa-abc-abcd-data-abc.com:1234/abc/abc/raw -H "Authorization: Splunk abc-hwhuhw1-dshjhsj-whdedg" -d {\"DATA_SET\":{\"NUMBER\":\"75\",\"TASK_URL\":\"https://abc.com/xyz/task/abcabc/\",\"DATA_URL\":\"https://abc.com/xyz/source/dataName/com.abc.team.data.DATA/\",\"PARTS\":[\"NAME\":\"abc.abc.abc\",\"SUB\":\"12345-\"]}}

The URL has some issue.

Re: unable to pass URL using curl command

PickleRick — Tue, 08 Feb 2022 08:21:19 GMT

Of course I didn't expect full raw data due to privacy issues 🙂

If you're typing this into shell, remember that you're hitting shell's expansion first.

See for yourself

$ echo {\"DATA_SET\":{\"NUMBER\":\"75\",\"TASK_URL\":\"https://abc.com/xyz/task/abcabc/\",\"DATA_URL\":\"https://abc.com/xyz/source/dataName/com.abc.team.data.DATA/\",\"PARTS\":[\"NAME\":\"abc.abc.abc\",\"SUB\":\"12345-\"]}}
{"DATA_SET":"NUMBER":"75"} {"DATA_SET":"TASK_URL":"https://abc.com/xyz/task/abcabc/"} {"DATA_SET":"DATA_URL":"https://abc.com/xyz/source/dataName/com.abc.team.data.DATA/"} {"DATA_SET":"PARTS":["NAME":"abc.abc.abc"} {"DATA_SET":"SUB":"12345-"]}

That's probably not what you want.

You should at least surround whole parameter to -d with quotes.

And next time, try curl with -v to easier see whether the issue is with the curl invocation syntax and curl won't even try to connect to the server in the first place or is it with the parameters/data syntax so that the error is returned by the server.

Re: unable to pass URL using curl command

anooshac — Tue, 08 Feb 2022 12:23:34 GMT

I removed DATA_SET. Tried executing with -v and it says {"text":"The requested URL was not found on this server.","code":404}. I guess it searching for the URL in the server mentioned in curl command.